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6w^2-34w-12=0
a = 6; b = -34; c = -12;
Δ = b2-4ac
Δ = -342-4·6·(-12)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-38}{2*6}=\frac{-4}{12} =-1/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+38}{2*6}=\frac{72}{12} =6 $
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